975=375+80x+4x^2

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Solution for 975=375+80x+4x^2 equation:



975=375+80x+4x^2
We move all terms to the left:
975-(375+80x+4x^2)=0
We get rid of parentheses
-4x^2-80x-375+975=0
We add all the numbers together, and all the variables
-4x^2-80x+600=0
a = -4; b = -80; c = +600;
Δ = b2-4ac
Δ = -802-4·(-4)·600
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-40\sqrt{10}}{2*-4}=\frac{80-40\sqrt{10}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+40\sqrt{10}}{2*-4}=\frac{80+40\sqrt{10}}{-8} $

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